tmp/tmphm8bxc4d/{from.md → to.md}
RENAMED
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@@ -34,56 +34,90 @@ and whose *template-parameter-list* consists of the specified
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call operator template is the *requires-clause* immediately following
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`<` *template-parameter-list* `>`, if any. The trailing
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*requires-clause* of the function call operator or operator template is
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the *requires-clause* of the *lambda-declarator*, if any.
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[*Note 2*: The function call operator template for a generic lambda
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-
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[*Example 1*:
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``` cpp
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auto glambda = [](auto a, auto&& b) { return a < b; };
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bool b = glambda(3, 3.14); // OK
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auto vglambda = [](auto printer) {
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return [=](auto&& ... ts) { // OK
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printer(std::forward<decltype(ts)>(ts)...);
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return [=]() {
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printer(ts ...);
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};
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};
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};
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auto p = vglambda( [](auto v1, auto v2, auto v3)
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{ std::cout << v1 << v2 << v3; } );
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auto q = p(1, 'a', 3.14); // OK
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q(); // OK
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```
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— *end example*]
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The function call operator or operator template is
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[[class.
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*parameter-declaration-clause* is
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neither virtual nor declared `volatile`. Any *noexcept-specifier*
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specified on a *lambda-expression* applies to the corresponding function
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call operator or operator template. An *attribute-specifier-seq* in a
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*lambda-declarator* appertains to the type of the corresponding function
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call operator or operator template.
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-
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-
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-
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-
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immediate function [[dcl.constexpr]] if the corresponding
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*lambda-expression*'s *parameter-declaration-clause* is followed by
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`consteval`.
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[*
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the context in which the *lambda-expression* appears. — *end note*]
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-
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[*Example 2*:
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``` cpp
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auto ID = [](auto a) { return a; };
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static_assert(ID(3) == 3); // OK
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@@ -94,11 +128,11 @@ struct NonLiteral {
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static_assert(ID(NonLiteral{3}).n == 3); // error
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```
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— *end example*]
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[*Example
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``` cpp
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auto monoid = [](auto v) { return [=] { return v; }; };
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auto add = [](auto m1) constexpr {
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auto ret = m1();
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@@ -123,18 +157,18 @@ static_assert(add(one)(one)() == two()); // error: two() is not a constan
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static_assert(add(one)(one)() == monoid(2)()); // OK
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```
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— *end example*]
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[*Note
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The function call operator or operator template
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[[temp.constr.decl]] by a *type-constraint* [[temp.param]], a
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*requires-clause* [[temp.pre]], or a trailing *requires-clause*
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[[dcl.decl]].
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[*Example
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``` cpp
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template <typename T> concept C1 = ...;
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template <std::size_t N> concept C2 = ...;
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template <typename A, typename B> concept C3 = ...;
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@@ -155,27 +189,29 @@ The closure type for a non-generic *lambda-expression* with no
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*lambda-capture* whose constraints (if any) are satisfied has a
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conversion function to pointer to function with C++ language linkage
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[[dcl.link]] having the same parameter and return types as the closure
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type’s function call operator. The conversion is to “pointer to
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`noexcept` function” if the function call operator has a non-throwing
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exception specification.
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-
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-
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-
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function
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For a generic lambda with no *lambda-capture*, the closure type has a
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conversion function template to pointer to function. The conversion
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function template has the same invented template parameter list, and the
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pointer to function has the same parameter types, as the function call
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operator template. The return type of the pointer to function shall
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behave as if it were a *decltype-specifier* denoting the return type of
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the corresponding function call operator template specialization.
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[*Note
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If the generic lambda has no *trailing-return-type* or the
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*trailing-return-type* contains a placeholder type, return type
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deduction of the corresponding function call operator template
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specialization has to be done. The corresponding specialization is that
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@@ -207,11 +243,11 @@ struct Closure {
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};
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```
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— *end note*]
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[*Example
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``` cpp
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void f1(int (*)(int)) { }
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void f2(char (*)(int)) { }
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@@ -223,45 +259,49 @@ void h(char (*)(int)) { } // #4
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auto glambda = [](auto a) { return a; };
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f1(glambda); // OK
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f2(glambda); // error: ID is not convertible
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g(glambda); // error: ambiguous
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h(glambda); // OK
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int& (*fpi)(int*) = [](auto* a) -> auto& { return *a; }; // OK
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```
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— *end example*]
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-
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-
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-
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function call operator template specialization
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-
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-
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-
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[*Note
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generic lambda’s body. The instantiated generic lambda’s return type and
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parameter types are required to match the return type and parameter
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types of the pointer to function. — *end note*]
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[*Example
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``` cpp
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auto GL = [](auto a) { std::cout << a; return a; };
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int (*GL_int)(int) = GL; // OK
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GL_int(3); // OK
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```
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— *end example*]
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The conversion function or conversion function template is public,
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constexpr, non-virtual, non-explicit, const, and has a non-throwing
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exception specification [[except.spec]].
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[*Example
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``` cpp
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auto Fwd = [](int (*fp)(int), auto a) { return fp(a); };
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auto C = [](auto a) { return a; };
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@@ -273,18 +313,14 @@ static_assert(Fwd(NC,3) == 3); // error
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```
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— *end example*]
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The *lambda-expression*’s *compound-statement* yields the
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*function-body* [[dcl.fct.def]] of the function call operator, but
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of `this` [[class.this]] and transforming *id-expression*s referring to
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non-static class members into class member access expressions using
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`(*this)` ([[class.mfct.non-static]]), the *compound-statement* is
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considered in the context of the *lambda-expression*.
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[*Example
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``` cpp
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struct S1 {
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int x, y;
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int operator()(int);
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@@ -309,12 +345,12 @@ defaulted default constructor otherwise. It has a defaulted copy
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constructor and a defaulted move constructor [[class.copy.ctor]]. It has
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a deleted copy assignment operator if the *lambda-expression* has a
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*lambda-capture* and defaulted copy and move assignment operators
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otherwise [[class.copy.assign]].
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[*Note
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usual,
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The closure type associated with a *lambda-expression* has an
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implicitly-declared destructor [[class.dtor]].
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A member of a closure type shall not be explicitly instantiated
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call operator template is the *requires-clause* immediately following
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`<` *template-parameter-list* `>`, if any. The trailing
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*requires-clause* of the function call operator or operator template is
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the *requires-clause* of the *lambda-declarator*, if any.
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[*Note 2*: The function call operator template for a generic lambda can
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be an abbreviated function template [[dcl.fct]]. — *end note*]
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[*Example 1*:
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``` cpp
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auto glambda = [](auto a, auto&& b) { return a < b; };
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bool b = glambda(3, 3.14); // OK
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auto vglambda = [](auto printer) {
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return [=](auto&& ... ts) { // OK, ts is a function parameter pack
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printer(std::forward<decltype(ts)>(ts)...);
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return [=]() {
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printer(ts ...);
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};
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};
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};
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auto p = vglambda( [](auto v1, auto v2, auto v3)
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{ std::cout << v1 << v2 << v3; } );
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auto q = p(1, 'a', 3.14); // OK, outputs 1a3.14
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q(); // OK, outputs 1a3.14
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auto fact = [](this auto self, int n) -> int { // OK, explicit object parameter
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return (n <= 1) ? 1 : n * self(n-1);
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};
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std::cout << fact(5); // OK, outputs 120
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```
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+
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— *end example*]
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Given a lambda with a *lambda-capture*, the type of the explicit object
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parameter, if any, of the lambda’s function call operator (possibly
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instantiated from a function call operator template) shall be either:
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- the closure type,
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- a class type derived from the closure type, or
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- a reference to a possibly cv-qualified such type.
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[*Example 2*:
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``` cpp
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struct C {
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template <typename T>
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C(T);
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};
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void func(int i) {
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int x = [=](this auto&&) { return i; }(); // OK
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int y = [=](this C) { return i; }(); // error
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int z = [](this C) { return 42; }(); // OK
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}
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```
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— *end example*]
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The function call operator or operator template is a static member
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function or static member function template [[class.static.mfct]] if the
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*lambda-expression*’s *parameter-declaration-clause* is followed by
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`static`. Otherwise, it is a non-static member function or member
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function template [[class.mfct.non.static]] that is declared `const`
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[[class.mfct.non.static]] if and only if the *lambda-expression*’s
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*parameter-declaration-clause* is not followed by `mutable` and the
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*lambda-declarator* does not contain an explicit object parameter. It is
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neither virtual nor declared `volatile`. Any *noexcept-specifier*
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specified on a *lambda-expression* applies to the corresponding function
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call operator or operator template. An *attribute-specifier-seq* in a
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*lambda-declarator* appertains to the type of the corresponding function
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call operator or operator template. An *attribute-specifier-seq* in a
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*lambda-expression* preceding a *lambda-declarator* appertains to the
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corresponding function call operator or operator template. The function
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call operator or any given operator template specialization is a
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constexpr function if either the corresponding *lambda-expression*'s
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*parameter-declaration-clause* is followed by `constexpr` or
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`consteval`, or it is constexpr-suitable [[dcl.constexpr]]. It is an
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immediate function [[dcl.constexpr]] if the corresponding
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*lambda-expression*'s *parameter-declaration-clause* is followed by
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`consteval`.
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[*Example 3*:
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``` cpp
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auto ID = [](auto a) { return a; };
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static_assert(ID(3) == 3); // OK
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static_assert(ID(NonLiteral{3}).n == 3); // error
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```
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— *end example*]
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[*Example 4*:
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``` cpp
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auto monoid = [](auto v) { return [=] { return v; }; };
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auto add = [](auto m1) constexpr {
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auto ret = m1();
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static_assert(add(one)(one)() == monoid(2)()); // OK
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```
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— *end example*]
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[*Note 3*:
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The function call operator or operator template can be constrained
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[[temp.constr.decl]] by a *type-constraint* [[temp.param]], a
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*requires-clause* [[temp.pre]], or a trailing *requires-clause*
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[[dcl.decl]].
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[*Example 5*:
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``` cpp
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template <typename T> concept C1 = ...;
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template <std::size_t N> concept C2 = ...;
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template <typename A, typename B> concept C3 = ...;
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*lambda-capture* whose constraints (if any) are satisfied has a
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conversion function to pointer to function with C++ language linkage
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[[dcl.link]] having the same parameter and return types as the closure
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type’s function call operator. The conversion is to “pointer to
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`noexcept` function” if the function call operator has a non-throwing
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exception specification. If the function call operator is a static
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member function, then the value returned by this conversion function is
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the address of the function call operator. Otherwise, the value returned
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by this conversion function is the address of a function `F` that, when
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invoked, has the same effect as invoking the closure type’s function
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call operator on a default-constructed instance of the closure type. `F`
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is a constexpr function if the function call operator is a constexpr
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function and is an immediate function if the function call operator is
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an immediate function.
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For a generic lambda with no *lambda-capture*, the closure type has a
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conversion function template to pointer to function. The conversion
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function template has the same invented template parameter list, and the
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pointer to function has the same parameter types, as the function call
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operator template. The return type of the pointer to function shall
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behave as if it were a *decltype-specifier* denoting the return type of
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the corresponding function call operator template specialization.
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[*Note 4*:
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If the generic lambda has no *trailing-return-type* or the
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*trailing-return-type* contains a placeholder type, return type
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deduction of the corresponding function call operator template
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specialization has to be done. The corresponding specialization is that
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};
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```
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— *end note*]
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[*Example 6*:
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``` cpp
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void f1(int (*)(int)) { }
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void f2(char (*)(int)) { }
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auto glambda = [](auto a) { return a; };
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f1(glambda); // OK
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f2(glambda); // error: ID is not convertible
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g(glambda); // error: ambiguous
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+
h(glambda); // OK, calls #3 since it is convertible from ID
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int& (*fpi)(int*) = [](auto* a) -> auto& { return *a; }; // OK
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```
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— *end example*]
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If the function call operator template is a static member function
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template, then the value returned by any given specialization of this
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conversion function template is the address of the corresponding
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function call operator template specialization. Otherwise, the value
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returned by any given specialization of this conversion function
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template is the address of a function `F` that, when invoked, has the
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same effect as invoking the generic lambda’s corresponding function call
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operator template specialization on a default-constructed instance of
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the closure type. `F` is a constexpr function if the corresponding
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specialization is a constexpr function and `F` is an immediate function
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if the function call operator template specialization is an immediate
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function.
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[*Note 5*: This will result in the implicit instantiation of the
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generic lambda’s body. The instantiated generic lambda’s return type and
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parameter types are required to match the return type and parameter
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types of the pointer to function. — *end note*]
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[*Example 7*:
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``` cpp
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auto GL = [](auto a) { std::cout << a; return a; };
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int (*GL_int)(int) = GL; // OK, through conversion function template
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GL_int(3); // OK, same as GL(3)
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```
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— *end example*]
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The conversion function or conversion function template is public,
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constexpr, non-virtual, non-explicit, const, and has a non-throwing
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exception specification [[except.spec]].
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[*Example 8*:
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``` cpp
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| 305 |
auto Fwd = [](int (*fp)(int), auto a) { return fp(a); };
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| 306 |
auto C = [](auto a) { return a; };
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| 307 |
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| 313 |
```
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| 314 |
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| 315 |
— *end example*]
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| 316 |
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| 317 |
The *lambda-expression*’s *compound-statement* yields the
|
| 318 |
+
*function-body* [[dcl.fct.def]] of the function call operator, but it is
|
| 319 |
+
not within the scope of the closure type.
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|
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|
|
| 320 |
|
| 321 |
+
[*Example 9*:
|
| 322 |
|
| 323 |
``` cpp
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| 324 |
struct S1 {
|
| 325 |
int x, y;
|
| 326 |
int operator()(int);
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|
|
|
| 345 |
constructor and a defaulted move constructor [[class.copy.ctor]]. It has
|
| 346 |
a deleted copy assignment operator if the *lambda-expression* has a
|
| 347 |
*lambda-capture* and defaulted copy and move assignment operators
|
| 348 |
otherwise [[class.copy.assign]].
|
| 349 |
|
| 350 |
+
[*Note 6*: These special member functions are implicitly defined as
|
| 351 |
+
usual, which can result in them being defined as deleted. — *end note*]
|
| 352 |
|
| 353 |
The closure type associated with a *lambda-expression* has an
|
| 354 |
implicitly-declared destructor [[class.dtor]].
|
| 355 |
|
| 356 |
A member of a closure type shall not be explicitly instantiated
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