tmp/tmpt6k_s0bk/{from.md → to.md}
RENAMED
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### The `constexpr`
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The `constexpr` specifier shall be applied only to the definition of a
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variable or variable template or the declaration of a function or
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function template.
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-
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-
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`constexpr`
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[*Note 1*: An explicit specialization can differ from the template
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declaration with respect to the `constexpr`
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[*Note 2*: Function parameters cannot be declared
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`constexpr`. — *end note*]
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[*Example 1*:
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@@ -26,11 +29,11 @@ constexpr struct pixel { // error: pixel is a type
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};
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constexpr pixel::pixel(int a)
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: x(a), y(x) // OK: definition
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{ square(x); }
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constexpr pixel small(2); // error: square not defined, so small(2)
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// not constant
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constexpr void square(int &x) { // OK: definition
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x *= x;
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}
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constexpr pixel large(4); // OK: square defined
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@@ -40,29 +43,33 @@ int next(constexpr int x) { // error: not for parameters
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extern constexpr int memsz; // error: not a definition
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```
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— *end example*]
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A `constexpr` specifier used in the declaration of a
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The definition of a constexpr function shall satisfy the following
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requirements:
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-
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- its return type shall be a literal type;
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- each of its parameter types shall be a literal type;
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-
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-
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-
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- a `goto` statement,
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- an identifier label
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- a *try-block*, or
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- a definition of a variable of non-literal type or of static or
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thread storage duration
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[*Example 2*:
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``` cpp
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constexpr int square(int x)
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@@ -77,12 +84,12 @@ constexpr int abs(int x) {
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constexpr int first(int n) {
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static int value = n; // error: variable has static storage duration
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return value;
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}
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constexpr int uninit() {
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int a;
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return a;
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}
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constexpr int prev(int x)
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{ return --x; } // OK
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constexpr int g(int x, int n) { // OK
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int r = 1;
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}
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```
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— *end example*]
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The definition of a constexpr constructor
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requirements:
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- the class shall not have any virtual base classes;
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- each of the parameter types shall be a literal type;
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- its *function-body* shall not be a *function-try-block*.
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In addition, either its *function-body* shall be `= delete`, or it shall
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satisfy the following requirements:
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- either its *function-body* shall be `= default`, or the
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*compound-statement* of its *function-body* shall satisfy the
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requirements for a *function-body* of a constexpr function;
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- every non-variant non-static data member and base class subobject
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shall be initialized ([[class.base.init]]);
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- if the class is a union having variant members ([[class.union]]),
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exactly one of them shall be initialized;
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- if the class is a union-like class, but is not a union, for each of
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its anonymous union members having variant members, exactly one of
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them shall be initialized;
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- for a non-delegating constructor, every constructor selected to
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initialize non-static data members and base class subobjects shall be
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a constexpr constructor;
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- for a delegating constructor, the target constructor shall be a
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constexpr constructor.
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@@ -129,16 +119,23 @@ private:
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};
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```
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— *end example*]
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For a constexpr function or constexpr constructor that is neither
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defaulted nor a template, if no argument values exist such that an
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invocation of the function or constructor could be an evaluated
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subexpression of a core constant expression
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constructor,
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required.
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[*Example 4*:
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``` cpp
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@@ -161,27 +158,33 @@ struct D : B {
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— *end example*]
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If the instantiated template specialization of a constexpr function
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template or member function of a class template would fail to satisfy
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the requirements for a constexpr function
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ill-formed, no diagnostic required.
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equivalent non-constexpr function in
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-
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[[expr.const]]
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- copy elision is
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-
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[*Example 5*:
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``` cpp
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constexpr int bar(int x, int y) // OK
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```
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— *end example*]
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A `constexpr` specifier used in an object declaration declares the
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object as
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initialized. In any `constexpr` variable declaration, the
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full-expression of the initialization shall be a constant expression
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[[expr.const]]
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[*Example 6*:
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``` cpp
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struct pixel {
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### The `constexpr` and `consteval` specifiers <a id="dcl.constexpr">[[dcl.constexpr]]</a>
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The `constexpr` specifier shall be applied only to the definition of a
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variable or variable template or the declaration of a function or
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function template. The `consteval` specifier shall be applied only to
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the declaration of a function or function template. A function or static
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data member declared with the `constexpr` or `consteval` specifier is
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implicitly an inline function or variable [[dcl.inline]]. If any
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declaration of a function or function template has a `constexpr` or
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`consteval` specifier, then all its declarations shall contain the same
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specifier.
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[*Note 1*: An explicit specialization can differ from the template
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declaration with respect to the `constexpr` or `consteval`
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specifier. — *end note*]
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[*Note 2*: Function parameters cannot be declared
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`constexpr`. — *end note*]
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[*Example 1*:
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};
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constexpr pixel::pixel(int a)
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: x(a), y(x) // OK: definition
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{ square(x); }
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constexpr pixel small(2); // error: square not defined, so small(2)
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// not constant[expr.const] so constexpr not satisfied
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constexpr void square(int &x) { // OK: definition
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x *= x;
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}
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constexpr pixel large(4); // OK: square defined
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extern constexpr int memsz; // error: not a definition
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```
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— *end example*]
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A `constexpr` or `consteval` specifier used in the declaration of a
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function declares that function to be a *constexpr function*. A function
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or constructor declared with the `consteval` specifier is called an
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*immediate function*. A destructor, an allocation function, or a
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deallocation function shall not be declared with the `consteval`
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specifier.
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The definition of a constexpr function shall satisfy the following
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requirements:
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- its return type (if any) shall be a literal type;
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- each of its parameter types shall be a literal type;
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- it shall not be a coroutine [[dcl.fct.def.coroutine]];
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- if the function is a constructor or destructor, its class shall not
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have any virtual base classes;
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- its *function-body* shall not enclose [[stmt.pre]]
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- a `goto` statement,
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- an identifier label [[stmt.label]],
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- a definition of a variable of non-literal type or of static or
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thread storage duration.
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\[*Note 3*: A *function-body* that is `= delete` or `= default`
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encloses none of the above. — *end note*]
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[*Example 2*:
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``` cpp
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constexpr int square(int x)
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constexpr int first(int n) {
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static int value = n; // error: variable has static storage duration
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return value;
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}
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constexpr int uninit() {
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struct { int a; } s;
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return s.a; // error: uninitialized read of s.a
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}
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constexpr int prev(int x)
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{ return --x; } // OK
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constexpr int g(int x, int n) { // OK
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int r = 1;
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}
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```
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— *end example*]
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The definition of a constexpr constructor whose *function-body* is not
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`= delete` shall additionally satisfy the following requirements:
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- for a non-delegating constructor, every constructor selected to
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initialize non-static data members and base class subobjects shall be
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a constexpr constructor;
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- for a delegating constructor, the target constructor shall be a
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constexpr constructor.
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};
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```
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— *end example*]
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The definition of a constexpr destructor whose *function-body* is not
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`= delete` shall additionally satisfy the following requirement:
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- for every subobject of class type or (possibly multi-dimensional)
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array thereof, that class type shall have a constexpr destructor.
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For a constexpr function or constexpr constructor that is neither
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defaulted nor a template, if no argument values exist such that an
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invocation of the function or constructor could be an evaluated
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subexpression of a core constant expression [[expr.const]], or, for a
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constructor, an evaluated subexpression of the initialization
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full-expression of some constant-initialized object
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[[basic.start.static]], the program is ill-formed, no diagnostic
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required.
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[*Example 4*:
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``` cpp
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— *end example*]
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If the instantiated template specialization of a constexpr function
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template or member function of a class template would fail to satisfy
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the requirements for a constexpr function, that specialization is still
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a constexpr function, even though a call to such a function cannot
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appear in a constant expression. If no specialization of the template
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would satisfy the requirements for a constexpr function when considered
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as a non-template function, the template is ill-formed, no diagnostic
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required.
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An invocation of a constexpr function in a given context produces the
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same result as an invocation of an equivalent non-constexpr function in
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the same context in all respects except that
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- an invocation of a constexpr function can appear in a constant
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expression [[expr.const]] and
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- copy elision is not performed in a constant expression
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[[class.copy.elision]].
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[*Note 4*: Declaring a function constexpr can change whether an
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expression is a constant expression. This can indirectly cause calls to
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`std::is_constant_evaluated` within an invocation of the function to
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produce a different value. — *end note*]
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The `constexpr` and `consteval` specifiers have no effect on the type of
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a constexpr function.
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[*Example 5*:
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``` cpp
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constexpr int bar(int x, int y) // OK
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```
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— *end example*]
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A `constexpr` specifier used in an object declaration declares the
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object as const. Such an object shall have literal type and shall be
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initialized. In any `constexpr` variable declaration, the
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full-expression of the initialization shall be a constant expression
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[[expr.const]]. A `constexpr` variable shall have constant destruction.
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[*Example 6*:
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``` cpp
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struct pixel {
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