tmp/tmpqu6u_hlu/{from.md → to.md}
RENAMED
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### The `constexpr` specifier <a id="dcl.constexpr">[[dcl.constexpr]]</a>
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The `constexpr` specifier shall be applied only to the definition of a
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variable or variable template
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template
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-
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-
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-
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``` cpp
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constexpr void square(int &x); // OK: declaration
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constexpr int bufsz = 1024; // OK: definition
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constexpr struct pixel { // error: pixel is a type
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@@ -32,31 +38,34 @@ int next(constexpr int x) { // error: not for parameters
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return x + 1;
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}
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extern constexpr int memsz; // error: not a definition
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```
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A `constexpr` specifier used in the declaration of a function that is
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not a constructor declares that function to be a *constexpr function*.
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Similarly, a `constexpr` specifier used in a constructor declaration
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declares that constructor to be a *constexpr constructor*.
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functions and `constexpr` constructors are implicitly `inline` (
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[[dcl.fct.spec]]).
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The definition of a
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-
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- it shall not be virtual ([[class.virtual]]);
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- its return type shall be a literal type;
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- each of its parameter types shall be a literal type;
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- its *function-body* shall be `= delete`, `= default`, or a
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*compound-statement* that does not contain
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- an *asm-definition*,
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- a `goto` statement,
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- a *try-block*, or
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- a definition of a variable of non-literal type or of static or
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thread storage duration or for which no initialization is performed.
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``` cpp
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constexpr int square(int x)
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{ return x * x; } // OK
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constexpr long long_max()
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{ return 2147483647; } // OK
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@@ -80,51 +89,60 @@ constexpr int g(int x, int n) { // OK
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while (--n > 0) r *= x;
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return r;
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}
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```
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-
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-
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- the class shall not have any virtual base classes;
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- each of the parameter types shall be a literal type;
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- its *function-body* shall not be a *function-try-block*
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In addition, either its *function-body* shall be `= delete`, or it shall
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satisfy the following
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- either its *function-body* shall be `= default`, or the
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*compound-statement* of its *function-body* shall satisfy the
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-
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- every non-variant non-static data member and base class
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shall be initialized ([[class.base.init]]);
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- if the class is a union having variant members ([[class.union]]),
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exactly one of them shall be initialized;
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- if the class is a union-like class, but is not a union, for each of
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its anonymous union members having variant members, exactly one of
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them shall be initialized;
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- for a non-delegating constructor, every constructor selected to
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initialize non-static data members and base class
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a
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- for a delegating constructor, the target constructor shall be a
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-
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``` cpp
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struct Length {
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constexpr explicit Length(int i = 0) : val(i) { }
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private:
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int val;
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};
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```
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-
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-
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-
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-
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-
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required.
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``` cpp
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constexpr int f(bool b)
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{ return b ? throw 0 : 0; } // OK
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constexpr int f() { return f(true); } // ill-formed, no diagnostic required
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@@ -139,48 +157,57 @@ struct D : B {
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constexpr D() : B(global) { } // ill-formed, no diagnostic required
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// lvalue-to-rvalue conversion on non-constant global
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};
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```
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-
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template or member function of a class template would fail to satisfy
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the requirements for a
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-
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-
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-
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-
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-
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-
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-
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A call to a
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-
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-
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-
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-
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``` cpp
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constexpr int bar(int x, int y) // OK
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{ return x + y + x*y; }
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// ...
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int bar(int x, int y) // error: redefinition of bar
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{ return x * 2 + 3 * y; }
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```
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A `constexpr` specifier used in an object declaration declares the
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object as `const`. Such an object shall have literal type and shall be
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initialized.
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be a constant expression (
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-
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-
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-
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expressions and each constructor call used for the initialization is
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part of such a full-expression.
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``` cpp
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struct pixel {
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int x, y;
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};
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constexpr pixel ur = { 1294, 1024 }; // OK
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constexpr pixel origin; // error: initializer missing
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```
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### The `constexpr` specifier <a id="dcl.constexpr">[[dcl.constexpr]]</a>
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The `constexpr` specifier shall be applied only to the definition of a
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variable or variable template or the declaration of a function or
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function template. A function or static data member declared with the
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`constexpr` specifier is implicitly an inline function or variable (
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[[dcl.inline]]). If any declaration of a function or function template
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has a `constexpr` specifier, then all its declarations shall contain the
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`constexpr` specifier.
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[*Note 1*: An explicit specialization can differ from the template
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declaration with respect to the `constexpr` specifier. — *end note*]
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[*Note 2*: Function parameters cannot be declared
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`constexpr`. — *end note*]
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[*Example 1*:
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``` cpp
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constexpr void square(int &x); // OK: declaration
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constexpr int bufsz = 1024; // OK: definition
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constexpr struct pixel { // error: pixel is a type
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return x + 1;
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}
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extern constexpr int memsz; // error: not a definition
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```
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— *end example*]
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A `constexpr` specifier used in the declaration of a function that is
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not a constructor declares that function to be a *constexpr function*.
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Similarly, a `constexpr` specifier used in a constructor declaration
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declares that constructor to be a *constexpr constructor*.
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The definition of a constexpr function shall satisfy the following
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requirements:
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- it shall not be virtual ([[class.virtual]]);
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- its return type shall be a literal type;
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- each of its parameter types shall be a literal type;
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- its *function-body* shall be `= delete`, `= default`, or a
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*compound-statement* that does not contain
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- an *asm-definition*,
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- a `goto` statement,
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- an identifier label ([[stmt.label]]),
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- a *try-block*, or
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- a definition of a variable of non-literal type or of static or
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thread storage duration or for which no initialization is performed.
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[*Example 2*:
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``` cpp
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constexpr int square(int x)
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{ return x * x; } // OK
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constexpr long long_max()
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{ return 2147483647; } // OK
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while (--n > 0) r *= x;
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return r;
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}
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```
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— *end example*]
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The definition of a constexpr constructor shall satisfy the following
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requirements:
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- the class shall not have any virtual base classes;
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- each of the parameter types shall be a literal type;
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- its *function-body* shall not be a *function-try-block*.
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In addition, either its *function-body* shall be `= delete`, or it shall
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satisfy the following requirements:
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- either its *function-body* shall be `= default`, or the
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*compound-statement* of its *function-body* shall satisfy the
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requirements for a *function-body* of a constexpr function;
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- every non-variant non-static data member and base class subobject
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shall be initialized ([[class.base.init]]);
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- if the class is a union having variant members ([[class.union]]),
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exactly one of them shall be initialized;
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- if the class is a union-like class, but is not a union, for each of
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its anonymous union members having variant members, exactly one of
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them shall be initialized;
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- for a non-delegating constructor, every constructor selected to
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initialize non-static data members and base class subobjects shall be
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a constexpr constructor;
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- for a delegating constructor, the target constructor shall be a
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constexpr constructor.
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+
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[*Example 3*:
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``` cpp
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struct Length {
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constexpr explicit Length(int i = 0) : val(i) { }
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private:
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int val;
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};
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```
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— *end example*]
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For a constexpr function or constexpr constructor that is neither
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defaulted nor a template, if no argument values exist such that an
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invocation of the function or constructor could be an evaluated
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subexpression of a core constant expression ([[expr.const]]), or, for a
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constructor, a constant initializer for some object (
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[[basic.start.static]]), the program is ill-formed, no diagnostic
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required.
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[*Example 4*:
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``` cpp
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constexpr int f(bool b)
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{ return b ? throw 0 : 0; } // OK
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constexpr int f() { return f(true); } // ill-formed, no diagnostic required
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constexpr D() : B(global) { } // ill-formed, no diagnostic required
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// lvalue-to-rvalue conversion on non-constant global
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};
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```
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— *end example*]
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If the instantiated template specialization of a constexpr function
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template or member function of a class template would fail to satisfy
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the requirements for a constexpr function or constexpr constructor, that
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specialization is still a constexpr function or constexpr constructor,
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even though a call to such a function cannot appear in a constant
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expression. If no specialization of the template would satisfy the
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requirements for a constexpr function or constexpr constructor when
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considered as a non-template function or constructor, the template is
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ill-formed, no diagnostic required.
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A call to a constexpr function produces the same result as a call to an
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equivalent non-constexpr function in all respects except that
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- a call to a constexpr function can appear in a constant expression (
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[[expr.const]]) and
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- copy elision is mandatory in a constant expression ([[class.copy]]).
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The `constexpr` specifier has no effect on the type of a constexpr
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function or a constexpr constructor.
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[*Example 5*:
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``` cpp
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constexpr int bar(int x, int y) // OK
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{ return x + y + x*y; }
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// ...
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int bar(int x, int y) // error: redefinition of bar
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{ return x * 2 + 3 * y; }
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```
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— *end example*]
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A `constexpr` specifier used in an object declaration declares the
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object as `const`. Such an object shall have literal type and shall be
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initialized. In any `constexpr` variable declaration, the
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full-expression of the initialization shall be a constant expression (
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[[expr.const]]).
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[*Example 6*:
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``` cpp
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struct pixel {
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int x, y;
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};
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constexpr pixel ur = { 1294, 1024 }; // OK
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constexpr pixel origin; // error: initializer missing
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```
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— *end example*]
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+
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