From Jason Turner

[temp.spec.partial.match]

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+ #### Matching of partial specializations <a id="temp.spec.partial.match">[[temp.spec.partial.match]]</a>
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+
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+ When a template is used in a context that requires an instantiation of
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+ the template, it is necessary to determine whether the instantiation is
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+ to be generated using the primary template or one of the partial
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+ specializations. This is done by matching the template arguments of the
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+ template specialization with the template argument lists of the partial
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+ specializations.
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+
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+ - If exactly one matching partial specialization is found, the
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+ instantiation is generated from that partial specialization.
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+ - If more than one matching partial specialization is found, the partial
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+ order rules [[temp.spec.partial.order]] are used to determine whether
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+ one of the partial specializations is more specialized than the
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+ others. If such a partial specialization exists, the instantiation is
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+ generated from that partial specialization; otherwise, the use of the
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+ template is ambiguous and the program is ill-formed.
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+ - If no matches are found, the instantiation is generated from the
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+ primary template.
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+
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+ A partial specialization matches a given actual template argument list
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+ if the template arguments of the partial specialization can be deduced
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+ from the actual template argument list [[temp.deduct]], and the deduced
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+ template arguments satisfy the associated constraints of the partial
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+ specialization, if any [[temp.constr.decl]].
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+
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+ [*Example 1*:
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+
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+ ``` cpp
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+ template<class T1, class T2, int I> class A { }; // #1
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+ template<class T, int I> class A<T, T*, I> { }; // #2
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+ template<class T1, class T2, int I> class A<T1*, T2, I> { }; // #3
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+ template<class T> class A<int, T*, 5> { }; // #4
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+ template<class T1, class T2, int I> class A<T1, T2*, I> { }; // #5
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+
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+ A<int, int, 1> a1; // uses #1
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+ A<int, int*, 1> a2; // uses #2, T is int, I is 1
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+ A<int, char*, 5> a3; // uses #4, T is char
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+ A<int, char*, 1> a4; // uses #5, T1 is int, T2 is char, I is 1
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+ A<int*, int*, 2> a5; // ambiguous: matches #3 and #5
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+ ```
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+
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+ — *end example*]
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+
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+ [*Example 2*:
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+
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+ ``` cpp
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+ template<typename T> concept C = requires (T t) { t.f(); };
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+
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+ template<typename T> struct S { }; // #1
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+ template<C T> struct S<T> { }; // #2
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+
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+ struct Arg { void f(); };
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+
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+ S<int> s1; // uses #1; the constraints of #2 are not satisfied
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+ S<Arg> s2; // uses #2; both constraints are satisfied but #2 is more specialized
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+ ```
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+
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+ — *end example*]
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+
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+ If the template arguments of a partial specialization cannot be deduced
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+ because of the structure of its *template-parameter-list* and the
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+ *template-id*, the program is ill-formed.
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+
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+ [*Example 3*:
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+
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+ ``` cpp
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+ template <int I, int J> struct A {};
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+ template <int I> struct A<I+5, I*2> {}; // error
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+
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+ template <int I> struct A<I, I> {}; // OK
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+
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+ template <int I, int J, int K> struct B {};
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+ template <int I> struct B<I, I*2, 2> {}; // OK
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+ ```
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+
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+ — *end example*]
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+
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+ In a name that refers to a specialization of a class or variable
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+ template (e.g., `A<int, int, 1>`), the argument list shall match the
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+ template parameter list of the primary template. The template arguments
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+ of a partial specialization are deduced from the arguments of the
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+ primary template.
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+