From Jason Turner

[time.traits.specializations]

Diff to HTML by rtfpessoa

tmp/tmpoecoet3e/{from.md → to.md} RENAMED
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- #### Specializations of `common_type` <a id="time.traits.specializations">[[time.traits.specializations]]</a>
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  ``` cpp
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  template<class Rep1, class Period1, class Rep2, class Period2>
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  struct common_type<chrono::duration<Rep1, Period1>, chrono::duration<Rep2, Period2>> {
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  using type = chrono::duration<common_type_t<Rep1, Rep2>, see below>;
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  };
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  ```
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  The `period` of the `duration` indicated by this specialization of
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- `common_type` shall be the greatest common divisor of `Period1` and
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- `Period2`.
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  [*Note 1*: This can be computed by forming a ratio of the greatest
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  common divisor of `Period1::num` and `Period2::num` and the least common
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  multiple of `Period1::den` and `Period2::den`. — *end note*]
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+ ### Specializations of `common_type` <a id="time.traits.specializations">[[time.traits.specializations]]</a>
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  ``` cpp
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  template<class Rep1, class Period1, class Rep2, class Period2>
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  struct common_type<chrono::duration<Rep1, Period1>, chrono::duration<Rep2, Period2>> {
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  using type = chrono::duration<common_type_t<Rep1, Rep2>, see below>;
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  };
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  ```
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  The `period` of the `duration` indicated by this specialization of
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+ `common_type` is the greatest common divisor of `Period1` and `Period2`.
 
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  [*Note 1*: This can be computed by forming a ratio of the greatest
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  common divisor of `Period1::num` and `Period2::num` and the least common
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  multiple of `Period1::den` and `Period2::den`. — *end note*]
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