- tmp/tmpoqv4w795/{from.md → to.md} +125 -78
tmp/tmpoqv4w795/{from.md → to.md}
RENAMED
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@@ -3,21 +3,73 @@
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Unless a class template specialization has been explicitly
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instantiated ([[temp.explicit]]) or explicitly specialized (
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[[temp.expl.spec]]), the class template specialization is implicitly
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instantiated when the specialization is referenced in a context that
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requires a completely-defined object type or when the completeness of
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-
the class type affects the semantics of the program.
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``` cpp
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template<class T, class U>
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struct Outer {
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template<class X, class Y> struct Inner;
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@@ -33,28 +85,43 @@ Outer<int, int> outer; // error at #2
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defined but noted as being associated with a definition in
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`Outer<T, U>`.) \#2 is also a redeclaration of \#1a. It is noted as
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associated with a definition, so it is an invalid redeclaration of the
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same partial specialization.
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Unless a member of a class template or a member template has been
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explicitly instantiated or explicitly specialized, the specialization of
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the member is implicitly instantiated when the specialization is
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referenced in a context that requires the member definition to exist; in
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-
particular, the initialization (and any associated side
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static data member does not occur unless the static data member is
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itself used in a way that requires the definition of the static data
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member to exist.
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Unless a function template specialization has been explicitly
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instantiated or explicitly specialized, the function template
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specialization is implicitly instantiated when the specialization is
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referenced in a context that requires a function definition to exist.
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-
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-
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-
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-
template
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-
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``` cpp
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template<class T> struct Z {
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void f();
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void g();
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@@ -72,47 +139,25 @@ void h() {
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```
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Nothing in this example requires `class` `Z<double>`, `Z<int>::g()`, or
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`Z<char>::f()` to be implicitly instantiated.
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Unless a variable template specialization has been explicitly
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instantiated or explicitly specialized, the variable template
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specialization is implicitly instantiated when the specialization is
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used. A default template argument for a variable template is implicitly
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instantiated when the variable template is referenced in a context that
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requires the value of the default argument.
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-
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-
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or if the completeness of the class type might affect the semantics of
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the program. In particular, if the semantics of an expression depend on
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the member or base class lists of a class template specialization, the
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class template specialization is implicitly generated. For instance,
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deleting a pointer to class type depends on whether or not the class
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declares a destructor, and conversion between pointer to class types
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depends on the inheritance relationship between the two classes
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involved.
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-
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``` cpp
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-
template<class T> class B { /* ... */ };
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template<class T> class D : public B<T> { /* ... */ };
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-
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void f(void*);
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void f(B<int>*);
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-
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void g(D<int>* p, D<char>* pp, D<double>* ppp) {
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f(p); // instantiation of D<int> required: call f(B<int>*)
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B<char>* q = pp; // instantiation of D<char> required:
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// convert D<char>* to B<char>*
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delete ppp; // instantiation of D<double> required
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}
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```
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If the overload resolution process can determine the correct function to
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call without instantiating a class template definition, it is
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unspecified whether that instantiation actually takes place.
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``` cpp
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template <class T> struct S {
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operator int();
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};
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@@ -124,31 +169,21 @@ void g(S<int>& sr) {
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f(sr); // instantiation of S<int> allowed but not required
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// instantiation of S<float> allowed but not required
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};
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```
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-
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required and the template is declared but not defined, the program is
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ill-formed.
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-
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``` cpp
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template<class T> class X;
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-
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X<char> ch; // error: definition of X required
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```
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The implicit instantiation of a class template does not cause any static
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data members of that class to be implicitly instantiated.
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If a function template or a member function template specialization is
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used in a way that involves overload resolution, a declaration of the
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specialization is implicitly instantiated ([[temp.over]]).
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An implementation shall not implicitly instantiate a function template,
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a variable template, a member template, a non-virtual member function, a
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member class,
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-
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implementation implicitly instantiates a virtual member function of a
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class template if the virtual member function would not otherwise be
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instantiated. The use of a template specialization in a default argument
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shall not cause the template to be implicitly instantiated except that a
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class template may be instantiated where its complete type is needed to
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@@ -161,10 +196,12 @@ specializations are placed in the namespace where the template is
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defined. Implicitly instantiated specializations for members of a class
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template are placed in the namespace where the enclosing class template
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is defined. Implicitly instantiated member templates are placed in the
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namespace where the enclosing class or class template is defined.
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``` cpp
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namespace N {
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template<class T> class List {
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public:
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T* get();
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@@ -184,25 +221,29 @@ void g(Map<const char*,int>& m) {
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a call of `lt.get()` from `Map<const char*,int>::get()` would place
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`List<int>::get()` in the namespace `N` rather than in the global
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namespace.
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If a function template `f` is called in a way that requires a default
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argument to be used, the dependent names are looked up, the semantics
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constraints are checked, and the instantiation of any template used in
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the default argument is done as if the default argument had been an
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initializer used in a function template specialization with the same
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scope, the same template parameters and the same access as that of the
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function template `f` used at that point, except that the scope in which
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a closure type is declared ([[expr.prim.lambda]]) – and
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associated namespaces – remain as determined from the
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definition for the default argument. This analysis is
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argument instantiation*. The instantiated default
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as the argument of `f`.
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Each default argument is instantiated independently.
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``` cpp
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template<class T> void f(T x, T y = ydef(T()), T z = zdef(T()));
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class A { };
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@@ -213,31 +254,37 @@ void g(A a, A b, A c) {
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f(a, b); // default argument z = zdef(T()) instantiated
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f(a); // ill-formed; ydef is not declared
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}
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```
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-
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-
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-
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needed but has not yet been instantiated, the dependent names are looked
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up, the semantics constraints are checked, and the instantiation of any
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template used in the *
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-
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-
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[[temp.point]] defines the point of instantiation of a
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specialization.
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There is an implementation-defined quantity that specifies the limit
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the total depth of recursive instantiations, which
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than one template. The result of an infinite
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is undefined.
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``` cpp
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template<class T> class X {
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X<T>* p; // OK
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X<T*> a; // implicit generation of X<T> requires
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// the implicit instantiation of X<T*> which requires
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// the implicit instantiation of X<T**> which
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};
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```
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Unless a class template specialization has been explicitly
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instantiated ([[temp.explicit]]) or explicitly specialized (
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[[temp.expl.spec]]), the class template specialization is implicitly
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instantiated when the specialization is referenced in a context that
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requires a completely-defined object type or when the completeness of
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+
the class type affects the semantics of the program.
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+
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+
[*Note 1*: In particular, if the semantics of an expression depend on
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the member or base class lists of a class template specialization, the
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+
class template specialization is implicitly generated. For instance,
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deleting a pointer to class type depends on whether or not the class
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declares a destructor, and a conversion between pointers to class type
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depends on the inheritance relationship between the two classes
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involved. — *end note*]
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+
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+
[*Example 1*:
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+
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+
``` cpp
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+
template<class T> class B { ... };
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+
template<class T> class D : public B<T> { ... };
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+
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+
void f(void*);
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+
void f(B<int>*);
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+
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+
void g(D<int>* p, D<char>* pp, D<double>* ppp) {
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+
f(p); // instantiation of D<int> required: call f(B<int>*)
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+
B<char>* q = pp; // instantiation of D<char> required: convert D<char>* to B<char>*
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+
delete ppp; // instantiation of D<double> required
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+
}
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+
```
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+
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+
— *end example*]
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+
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+
If a class template has been declared, but not defined, at the point of
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instantiation ([[temp.point]]), the instantiation yields an incomplete
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class type ([[basic.types]]).
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+
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+
[*Example 2*:
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+
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| 42 |
+
``` cpp
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+
template<class T> class X;
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+
X<char> ch; // error: incomplete type X<char>
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+
```
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+
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+
— *end example*]
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+
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+
[*Note 2*: Within a template declaration, a local class (
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+
[[class.local]]) or enumeration and the members of a local class are
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+
never considered to be entities that can be separately instantiated
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+
(this includes their default arguments, *noexcept-specifier*s, and
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+
non-static data member initializers, if any). As a result, the dependent
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+
names are looked up, the semantic constraints are checked, and any
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+
templates used are instantiated as part of the instantiation of the
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+
entity within which the local class or enumeration is
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+
declared. — *end note*]
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+
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+
The implicit instantiation of a class template specialization causes the
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+
implicit instantiation of the declarations, but not of the definitions,
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+
default arguments, or *noexcept-specifier*s of the class member
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+
functions, member classes, scoped member enumerations, static data
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+
members, member templates, and friends; and it causes the implicit
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+
instantiation of the definitions of unscoped member enumerations and
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+
member anonymous unions. However, for the purpose of determining whether
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an instantiated redeclaration is valid according to [[basic.def.odr]]
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and [[class.mem]], a declaration that corresponds to a definition in the
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template is considered to be a definition.
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+
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+
[*Example 3*:
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``` cpp
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template<class T, class U>
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struct Outer {
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template<class X, class Y> struct Inner;
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defined but noted as being associated with a definition in
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`Outer<T, U>`.) \#2 is also a redeclaration of \#1a. It is noted as
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associated with a definition, so it is an invalid redeclaration of the
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same partial specialization.
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+
``` cpp
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+
template<typename T> struct Friendly {
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+
template<typename U> friend int f(U) { return sizeof(T); }
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+
};
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+
Friendly<char> fc;
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+
Friendly<float> ff; // ill-formed: produces second definition of f(U)
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+
```
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+
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+
— *end example*]
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+
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Unless a member of a class template or a member template has been
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explicitly instantiated or explicitly specialized, the specialization of
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the member is implicitly instantiated when the specialization is
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referenced in a context that requires the member definition to exist; in
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+
particular, the initialization (and any associated side effects) of a
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static data member does not occur unless the static data member is
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itself used in a way that requires the definition of the static data
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member to exist.
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Unless a function template specialization has been explicitly
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instantiated or explicitly specialized, the function template
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specialization is implicitly instantiated when the specialization is
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+
referenced in a context that requires a function definition to exist. A
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+
function whose declaration was instantiated from a friend function
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+
definition is implicitly instantiated when it is referenced in a context
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+
that requires a function definition to exist. Unless a call is to a
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+
function template explicit specialization or to a member function of an
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+
explicitly specialized class template, a default argument for a function
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+
template or a member function of a class template is implicitly
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+
instantiated when the function is called in a context that requires the
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+
value of the default argument.
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+
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+
[*Example 4*:
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``` cpp
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| 125 |
template<class T> struct Z {
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| 126 |
void f();
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| 127 |
void g();
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| 139 |
```
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| 140 |
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| 141 |
Nothing in this example requires `class` `Z<double>`, `Z<int>::g()`, or
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| 142 |
`Z<char>::f()` to be implicitly instantiated.
|
| 143 |
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| 144 |
+
— *end example*]
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+
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| 146 |
Unless a variable template specialization has been explicitly
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| 147 |
instantiated or explicitly specialized, the variable template
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| 148 |
specialization is implicitly instantiated when the specialization is
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| 149 |
used. A default template argument for a variable template is implicitly
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| 150 |
instantiated when the variable template is referenced in a context that
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requires the value of the default argument.
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| 152 |
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+
If the function selected by overload resolution ([[over.match]]) can be
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+
determined without instantiating a class template definition, it is
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unspecified whether that instantiation actually takes place.
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+
[*Example 5*:
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+
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``` cpp
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| 160 |
template <class T> struct S {
|
| 161 |
operator int();
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};
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| 169 |
f(sr); // instantiation of S<int> allowed but not required
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// instantiation of S<float> allowed but not required
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};
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| 172 |
```
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+
— *end example*]
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If a function template or a member function template specialization is
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used in a way that involves overload resolution, a declaration of the
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specialization is implicitly instantiated ([[temp.over]]).
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| 180 |
An implementation shall not implicitly instantiate a function template,
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a variable template, a member template, a non-virtual member function, a
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+
member class, a static data member of a class template, or a
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+
substatement of a constexpr if statement ([[stmt.if]]), unless such
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+
instantiation is required. It is unspecified whether or not an
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| 185 |
implementation implicitly instantiates a virtual member function of a
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| 186 |
class template if the virtual member function would not otherwise be
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| 187 |
instantiated. The use of a template specialization in a default argument
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| 188 |
shall not cause the template to be implicitly instantiated except that a
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| 189 |
class template may be instantiated where its complete type is needed to
|
|
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| 196 |
defined. Implicitly instantiated specializations for members of a class
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| 197 |
template are placed in the namespace where the enclosing class template
|
| 198 |
is defined. Implicitly instantiated member templates are placed in the
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| 199 |
namespace where the enclosing class or class template is defined.
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+
[*Example 6*:
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+
|
| 203 |
``` cpp
|
| 204 |
namespace N {
|
| 205 |
template<class T> class List {
|
| 206 |
public:
|
| 207 |
T* get();
|
|
|
|
| 221 |
|
| 222 |
a call of `lt.get()` from `Map<const char*,int>::get()` would place
|
| 223 |
`List<int>::get()` in the namespace `N` rather than in the global
|
| 224 |
namespace.
|
| 225 |
|
| 226 |
+
— *end example*]
|
| 227 |
+
|
| 228 |
If a function template `f` is called in a way that requires a default
|
| 229 |
argument to be used, the dependent names are looked up, the semantics
|
| 230 |
constraints are checked, and the instantiation of any template used in
|
| 231 |
the default argument is done as if the default argument had been an
|
| 232 |
initializer used in a function template specialization with the same
|
| 233 |
scope, the same template parameters and the same access as that of the
|
| 234 |
function template `f` used at that point, except that the scope in which
|
| 235 |
+
a closure type is declared ([[expr.prim.lambda.closure]]) – and
|
| 236 |
+
therefore its associated namespaces – remain as determined from the
|
| 237 |
+
context of the definition for the default argument. This analysis is
|
| 238 |
+
called *default argument instantiation*. The instantiated default
|
| 239 |
+
argument is then used as the argument of `f`.
|
| 240 |
|
| 241 |
Each default argument is instantiated independently.
|
| 242 |
|
| 243 |
+
[*Example 7*:
|
| 244 |
+
|
| 245 |
``` cpp
|
| 246 |
template<class T> void f(T x, T y = ydef(T()), T z = zdef(T()));
|
| 247 |
|
| 248 |
class A { };
|
| 249 |
|
|
|
|
| 254 |
f(a, b); // default argument z = zdef(T()) instantiated
|
| 255 |
f(a); // ill-formed; ydef is not declared
|
| 256 |
}
|
| 257 |
```
|
| 258 |
|
| 259 |
+
— *end example*]
|
| 260 |
+
|
| 261 |
+
The *noexcept-specifier* of a function template specialization is not
|
| 262 |
+
instantiated along with the function declaration; it is instantiated
|
| 263 |
+
when needed ([[except.spec]]). If such an *noexcept-specifier* is
|
| 264 |
needed but has not yet been instantiated, the dependent names are looked
|
| 265 |
up, the semantics constraints are checked, and the instantiation of any
|
| 266 |
+
template used in the *noexcept-specifier* is done as if it were being
|
| 267 |
+
done as part of instantiating the declaration of the specialization at
|
| 268 |
+
that point.
|
| 269 |
|
| 270 |
+
[*Note 3*: [[temp.point]] defines the point of instantiation of a
|
| 271 |
+
template specialization. — *end note*]
|
| 272 |
|
| 273 |
+
There is an *implementation-defined* quantity that specifies the limit
|
| 274 |
+
on the total depth of recursive instantiations ([[implimits]]), which
|
| 275 |
+
could involve more than one template. The result of an infinite
|
| 276 |
+
recursion in instantiation is undefined.
|
| 277 |
+
|
| 278 |
+
[*Example 8*:
|
| 279 |
|
| 280 |
``` cpp
|
| 281 |
template<class T> class X {
|
| 282 |
X<T>* p; // OK
|
| 283 |
X<T*> a; // implicit generation of X<T> requires
|
| 284 |
// the implicit instantiation of X<T*> which requires
|
| 285 |
+
// the implicit instantiation of X<T**> which …
|
| 286 |
};
|
| 287 |
```
|
| 288 |
|
| 289 |
+
— *end example*]
|
| 290 |
+
|