tmp/tmp0atui3tx/{from.md → to.md}
RENAMED
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@@ -1,30 +1,31 @@
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#### Namespace members <a id="namespace.qual">[[namespace.qual]]</a>
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If the *nested-name-specifier* of a *qualified-id* nominates a
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occurs.
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For a namespace `X` and name `m`, the namespace-qualified lookup set
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S(X, m) is defined as follows: Let S'(X, m) be the set of all
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declarations of `m` in `X` and the inline namespace set of `X` (
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[[namespace.def]]). If S'(X, m) is not empty, S(X, m) is S'(X, m);
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otherwise, S(X, m) is the union of S(Nᵢ, m) for all namespaces Nᵢ
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nominated by *using-
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Given `X::m` (where `X` is a user-declared namespace), or given `::m`
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(where X is the global namespace), if S(X, m) is the empty set, the
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program is ill-formed. Otherwise, if S(X, m) has exactly one member, or
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if the context of the reference is a *using-declaration* (
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[[namespace.udecl]]), S(X, m) is the required set of declarations of
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`m`. Otherwise if the use of `m` is not one that allows a unique
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declaration to be chosen from S(X, m), the program is ill-formed.
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``` cpp
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int x;
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namespace Y {
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void f(float);
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void h(int);
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@@ -53,38 +54,38 @@ namespace AB {
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void g();
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}
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void h()
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{
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AB::g(); // g is declared directly in AB,
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-
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AB::f(1); // f is not declared directly in AB so the rules are
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//
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//
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// S is { A::f(int), B::f(char) } and overload
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// resolution chooses A::f(int)
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AB::f('c'); // as above but resolution chooses B::f(char)
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AB::x++; // x is not declared directly in AB, and
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//
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// and
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// not declared directly in A or B so the rules are
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// applied recursively to Y and Z,
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// S is { Y::h(int), Z::h(double) } and overload
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// resolution chooses Z::h(double)
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}
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```
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The same declaration found more than once is not an ambiguity (because
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it is still a unique declaration).
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``` cpp
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namespace A {
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int a;
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}
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@@ -102,11 +103,11 @@ namespace BC {
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using namespace C;
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}
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void f()
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{
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BC::a++; // OK: S is { A::a, A::a }
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}
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namespace D {
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using A::a;
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}
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@@ -116,14 +117,20 @@ namespace BD {
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using namespace D;
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}
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void g()
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{
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BD::a++; // OK: S is {
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}
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```
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Because each referenced namespace is searched at most once, the
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following is well-defined:
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``` cpp
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namespace B {
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@@ -139,25 +146,29 @@ namespace B {
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using namespace A;
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}
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void f()
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{
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A::a++; // OK: a declared directly in A, S is {A::a}
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B::a++; // OK: both A and B searched (once), S is {A::a}
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A::b++; // OK: both A and B searched (once), S is {B::b}
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B::b++; // OK: b declared directly in B, S is {B::b}
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}
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```
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During the lookup of a qualified namespace member name, if the lookup
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finds more than one declaration of the member, and if one declaration
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introduces a class name or enumeration name and the other declarations
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either introduce the same variable, the same enumerator or a set of
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functions, the non-type name hides the class or enumeration name if and
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only if the declarations are from the same namespace; otherwise (the
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declarations are from different namespaces), the program is ill-formed.
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``` cpp
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namespace A {
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struct x { };
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int x;
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int y;
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@@ -173,10 +184,12 @@ namespace C {
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int i = C::x; // OK, A::x (of type int)
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int j = C::y; // ambiguous, A::y or B::y
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}
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```
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In a declaration for a namespace member in which the *declarator-id* is
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a *qualified-id*, given that the *qualified-id* for the namespace member
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has the form
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``` bnf
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@@ -185,24 +198,30 @@ nested-name-specifier unqualified-id
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the *unqualified-id* shall name a member of the namespace designated by
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the *nested-name-specifier* or of an element of the inline namespace
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set ([[namespace.def]]) of that namespace.
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``` cpp
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namespace A {
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namespace B {
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void f1(int);
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}
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using namespace B;
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}
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void A::f1(int){ } // ill-formed, f1 is not a member of A
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```
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However, in such namespace member declarations, the
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*nested-name-specifier* may rely on *using-directive*s to implicitly
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provide the initial part of the *nested-name-specifier*.
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``` cpp
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namespace A {
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namespace B {
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void f1(int);
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}
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@@ -217,5 +236,7 @@ namespace C {
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using namespace A;
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using namespace C::D;
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void B::f1(int){ } // OK, defines A::B::f1(int)
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```
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#### Namespace members <a id="namespace.qual">[[namespace.qual]]</a>
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If the *nested-name-specifier* of a *qualified-id* nominates a namespace
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(including the case where the *nested-name-specifier* is `::`, i.e.,
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nominating the global namespace), the name specified after the
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*nested-name-specifier* is looked up in the scope of the namespace. The
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names in a *template-argument* of a *template-id* are looked up in the
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context in which the entire *postfix-expression* occurs.
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For a namespace `X` and name `m`, the namespace-qualified lookup set
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S(X, m) is defined as follows: Let S'(X, m) be the set of all
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declarations of `m` in `X` and the inline namespace set of `X` (
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[[namespace.def]]). If S'(X, m) is not empty, S(X, m) is S'(X, m);
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otherwise, S(X, m) is the union of S(Nᵢ, m) for all namespaces Nᵢ
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nominated by *using-directive*s in `X` and its inline namespace set.
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Given `X::m` (where `X` is a user-declared namespace), or given `::m`
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(where X is the global namespace), if S(X, m) is the empty set, the
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program is ill-formed. Otherwise, if S(X, m) has exactly one member, or
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if the context of the reference is a *using-declaration* (
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[[namespace.udecl]]), S(X, m) is the required set of declarations of
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`m`. Otherwise if the use of `m` is not one that allows a unique
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declaration to be chosen from S(X, m), the program is ill-formed.
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[*Example 1*:
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+
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``` cpp
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int x;
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namespace Y {
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void f(float);
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void h(int);
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void g();
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}
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void h()
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{
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AB::g(); // g is declared directly in AB, therefore S is { `AB::g()` } and AB::g() is chosen
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+
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AB::f(1); // f is not declared directly in AB so the rules are applied recursively to A and B;
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// namespace Y is not searched and Y::f(float) is not considered;
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// S is { `A::f(int)`, `B::f(char)` } and overload resolution chooses A::f(int)
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AB::f('c'); // as above but resolution chooses B::f(char)
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AB::x++; // x is not declared directly in AB, and is not declared in A or B, so the rules
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// are applied recursively to Y and Z, S is { } so the program is ill-formed
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AB::i++; // i is not declared directly in AB so the rules are applied recursively to A and B,
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// S is { `A::i`, `B::i` } so the use is ambiguous and the program is ill-formed
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+
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AB::h(16.8); // h is not declared directly in AB and not declared directly in A or B so the rules
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// are applied recursively to Y and Z, S is { `Y::h(int)`, `Z::h(double)` } and
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// overload resolution chooses Z::h(double)
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}
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```
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— *end example*]
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[*Note 1*:
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The same declaration found more than once is not an ambiguity (because
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it is still a unique declaration).
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+
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[*Example 2*:
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``` cpp
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namespace A {
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int a;
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}
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using namespace C;
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}
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void f()
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{
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BC::a++; // OK: S is { `A::a`, `A::a` }
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}
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namespace D {
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using A::a;
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}
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using namespace D;
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}
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void g()
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{
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BD::a++; // OK: S is { `A::a`, `A::a` }
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}
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```
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— *end example*]
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+
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— *end note*]
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[*Example 3*:
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Because each referenced namespace is searched at most once, the
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following is well-defined:
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``` cpp
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namespace B {
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using namespace A;
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}
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void f()
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{
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A::a++; // OK: a declared directly in A, S is { `A::a` }
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B::a++; // OK: both A and B searched (once), S is { `A::a` }
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A::b++; // OK: both A and B searched (once), S is { `B::b` }
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B::b++; // OK: b declared directly in B, S is { `B::b` }
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}
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```
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— *end example*]
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+
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During the lookup of a qualified namespace member name, if the lookup
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finds more than one declaration of the member, and if one declaration
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introduces a class name or enumeration name and the other declarations
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either introduce the same variable, the same enumerator or a set of
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functions, the non-type name hides the class or enumeration name if and
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only if the declarations are from the same namespace; otherwise (the
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declarations are from different namespaces), the program is ill-formed.
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+
[*Example 4*:
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+
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``` cpp
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namespace A {
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struct x { };
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int x;
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int y;
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int i = C::x; // OK, A::x (of type int)
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int j = C::y; // ambiguous, A::y or B::y
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}
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```
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— *end example*]
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+
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In a declaration for a namespace member in which the *declarator-id* is
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a *qualified-id*, given that the *qualified-id* for the namespace member
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has the form
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``` bnf
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the *unqualified-id* shall name a member of the namespace designated by
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the *nested-name-specifier* or of an element of the inline namespace
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set ([[namespace.def]]) of that namespace.
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+
[*Example 5*:
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+
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``` cpp
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namespace A {
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namespace B {
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void f1(int);
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}
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using namespace B;
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}
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void A::f1(int){ } // ill-formed, f1 is not a member of A
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```
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+
— *end example*]
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+
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However, in such namespace member declarations, the
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*nested-name-specifier* may rely on *using-directive*s to implicitly
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provide the initial part of the *nested-name-specifier*.
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+
[*Example 6*:
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+
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``` cpp
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namespace A {
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namespace B {
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void f1(int);
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}
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using namespace A;
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using namespace C::D;
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void B::f1(int){ } // OK, defines A::B::f1(int)
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```
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— *end example*]
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+
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