tmp/tmp88iygme_/{from.md → to.md}
RENAMED
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@@ -15,25 +15,31 @@ accessible as `private` members of the derived class[^8].
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In the absence of an *access-specifier* for a base class, `public` is
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assumed when the derived class is defined with the *class-key* `struct`
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and `private` is assumed when the class is defined with the *class-key*
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`class`.
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``` cpp
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class B {
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class D1 : private B {
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class D2 : public B {
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class D3 : B {
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struct D4 : public B {
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struct D5 : private B {
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struct D6 : B {
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class D7 : protected B {
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struct D8 : protected B {
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```
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Here `B` is a public base of `D2`, `D4`, and `D6`, a private base of
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`D1`, `D3`, and `D5`, and a protected base of `D7` and `D8`.
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A member of a private base class might be inaccessible as an inherited
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member name, but accessible directly. Because of the rules on pointer
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conversions ([[conv.ptr]]) and explicit casts ([[expr.cast]]), a
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conversion from a pointer to a derived class to a pointer to an
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inaccessible base class might be ill-formed if an implicit conversion is
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@@ -62,10 +68,12 @@ void DD::f() {
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::B* bp2 = (::B*)this; // OK with cast
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bp2->mi = 3; // OK: access through a pointer to B.
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}
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```
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A base class `B` of `N` is *accessible* at *R*, if
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- an invented public member of `B` would be a public member of `N`, or
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- *R* occurs in a member or friend of class `N`, and an invented public
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member of `B` would be a private or protected member of `N`, or
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@@ -73,10 +81,12 @@ A base class `B` of `N` is *accessible* at *R*, if
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an invented public member of `B` would be a private or protected
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member of `P`, or
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- there exists a class `S` such that `B` is a base class of `S`
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accessible at *R* and `S` is a base class of `N` accessible at *R*.
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``` cpp
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class B {
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public:
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int m;
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};
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@@ -85,58 +95,69 @@ class S: private B {
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friend class N;
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};
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class N: private S {
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void f() {
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B* p = this; // OK because class S satisfies the fourth condition
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//
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// B is an accessible base class of S and S is an accessible
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// base class of N.
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}
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};
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```
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If a base class is accessible, one can implicitly convert a pointer to a
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derived class to a pointer to that base class ([[conv.ptr]],
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[[conv.mem]]).
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implicitly convert an `X*` to a pointer to a private or protected
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immediate base class of `X`.
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-
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-
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-
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-
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- `m` as a member of `N` is public, or
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- `m` as a member of `N` is private, and *R* occurs in a member or
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friend of class `N`, or
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- `m` as a member of `N` is protected, and *R* occurs in a member or
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friend of class `N`, or in a member
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-
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protected, or
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- there exists a base class `B` of `N` that is accessible at *R*, and
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`m` is accessible at *R* when named in class `B`.
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``` cpp
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class B;
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class A {
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private:
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int i;
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friend void f(B*);
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};
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class B : public A { };
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void f(B* p) {
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p->i = 1; // OK: B* can be implicitly converted to A*,
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// and f has access to i in A
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}
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```
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-
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used to access a non-static data member or non-static member function,
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the reference is ill-formed if the left operand (considered as a pointer
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in the “`.`” operator case) cannot be implicitly converted to a pointer
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to the naming class of the right operand.
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-
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In the absence of an *access-specifier* for a base class, `public` is
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assumed when the derived class is defined with the *class-key* `struct`
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and `private` is assumed when the class is defined with the *class-key*
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`class`.
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+
[*Example 1*:
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+
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``` cpp
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class B { ... };
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class D1 : private B { ... };
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class D2 : public B { ... };
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class D3 : B { ... }; // B private by default
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struct D4 : public B { ... };
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struct D5 : private B { ... };
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struct D6 : B { ... }; // B public by default
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class D7 : protected B { ... };
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struct D8 : protected B { ... };
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```
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Here `B` is a public base of `D2`, `D4`, and `D6`, a private base of
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`D1`, `D3`, and `D5`, and a protected base of `D7` and `D8`.
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— *end example*]
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+
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[*Note 1*:
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A member of a private base class might be inaccessible as an inherited
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member name, but accessible directly. Because of the rules on pointer
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conversions ([[conv.ptr]]) and explicit casts ([[expr.cast]]), a
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conversion from a pointer to a derived class to a pointer to an
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inaccessible base class might be ill-formed if an implicit conversion is
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::B* bp2 = (::B*)this; // OK with cast
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bp2->mi = 3; // OK: access through a pointer to B.
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}
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```
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— *end note*]
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+
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A base class `B` of `N` is *accessible* at *R*, if
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- an invented public member of `B` would be a public member of `N`, or
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- *R* occurs in a member or friend of class `N`, and an invented public
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member of `B` would be a private or protected member of `N`, or
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an invented public member of `B` would be a private or protected
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member of `P`, or
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- there exists a class `S` such that `B` is a base class of `S`
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accessible at *R* and `S` is a base class of `N` accessible at *R*.
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[*Example 2*:
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``` cpp
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class B {
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public:
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int m;
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};
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friend class N;
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};
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class N: private S {
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void f() {
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B* p = this; // OK because class S satisfies the fourth condition above: B is a base class of N
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// accessible in f() because B is an accessible base class of S and S is an accessible
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// base class of N.
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}
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};
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```
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— *end example*]
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If a base class is accessible, one can implicitly convert a pointer to a
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derived class to a pointer to that base class ([[conv.ptr]],
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[[conv.mem]]).
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[*Note 2*: It follows that members and friends of a class `X` can
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implicitly convert an `X*` to a pointer to a private or protected
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immediate base class of `X`. — *end note*]
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The access to a member is affected by the class in which the member is
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named. This naming class is the class in which the member name was
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looked up and found.
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[*Note 3*: This class can be explicit, e.g., when a *qualified-id* is
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used, or implicit, e.g., when a class member access operator (
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[[expr.ref]]) is used (including cases where an implicit “`this->`” is
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added). If both a class member access operator and a *qualified-id* are
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used to name the member (as in `p->T::m`), the class naming the member
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is the class denoted by the *nested-name-specifier* of the
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*qualified-id* (that is, `T`). — *end note*]
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A member `m` is accessible at the point *R* when named in class `N` if
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- `m` as a member of `N` is public, or
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- `m` as a member of `N` is private, and *R* occurs in a member or
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friend of class `N`, or
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- `m` as a member of `N` is protected, and *R* occurs in a member or
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friend of class `N`, or in a member of a class `P` derived from `N`,
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where `m` as a member of `P` is public, private, or protected, or
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- there exists a base class `B` of `N` that is accessible at *R*, and
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`m` is accessible at *R* when named in class `B`.
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+
\[*Example 3*:
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``` cpp
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class B;
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class A {
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private:
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int i;
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friend void f(B*);
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};
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class B : public A { };
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void f(B* p) {
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p->i = 1; // OK: B* can be implicitly converted to A*, and f has access to i in A
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}
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```
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— *end example*]
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+
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If a class member access operator, including an implicit “`this->`”, is
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used to access a non-static data member or non-static member function,
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the reference is ill-formed if the left operand (considered as a pointer
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in the “`.`” operator case) cannot be implicitly converted to a pointer
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to the naming class of the right operand.
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+
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[*Note 4*: This requirement is in addition to the requirement that the
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member be accessible as named. — *end note*]
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